find the roots of the equation x²+2x-3=O
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The roots of the equation are 1 and -3.....
shishir38:
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We have,
x^2+2x-3=0
x^2+3x-x-3=0
x( x+3 ) - ( x+3 )=0
( x-1 ) (x+3 )=0
x=1 and x= -3
x^2+2x-3=0
x^2+3x-x-3=0
x( x+3 ) - ( x+3 )=0
( x-1 ) (x+3 )=0
x=1 and x= -3
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