Question

Find the roots of the equation x2 – 3x – m(m + 3) = 0, where, mis a constant.​

Answer 1

Answer:

x2-3x-m(m+3)=0

D=b2-4ac

=〖(-3〗2)- 4×1×-m(m+3)

=9 – 4 ×-m2-3m

=9+〖4m〗2+12m

=4m2+12m+9

=〖(2m)〗2+2×(2m)×3+32

=(2m+3)2

√(D ) =2m+3

x=(-b±√(b2-4ac)) / 2a

=(3+(2m+3))/(2×1)

= (6+2m)/2

= 6/2+2m/2 = 3+m

x = (-b±√(b2-4ac))/2a

= (3-(2m+3))/(2×1)

= (3-2m-3)/2 = -m

ANS : (-M,M+3)