Question

find the roots of the equation x2-3x-m2-3m=0where m is a constant.

Answer 1

Answer:

Roots = - m and m+3

Step-by-step explanation:

I think u mean=> x²-3x-m (2-3)=0

x² - 3x - m(m+3) = 0

=> x² + mx - (m+3)x- m(m+3) = 0

=> x(x+m) - (m+3)(x+m) = 0

=> (x+m) (x-m-3) = 0

x = - m and m+3