find the roots of the equation x2-3x-m2-3m=0where m is a constant.
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Answer:
Roots = - m and m+3
Step-by-step explanation:
I think u mean=> x²-3x-m (2-3)=0
x² - 3x - m(m+3) = 0
=> x² + mx - (m+3)x- m(m+3) = 0
=> x(x+m) - (m+3)(x+m) = 0
=> (x+m) (x-m-3) = 0
x = - m and m+3
akanshamathur13:
l have not understand can you plz explain me how you factorized it
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