Question

Find the roots of the equation x2 +6x + 8 = 0.

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Answer 1

Use the quadratic formula

=

−

±

2

−

4

√

2

x=\frac{-{\color{#e8710a}{b}} \pm \sqrt{{\color{#e8710a}{b}}^{2}-4{\color{#c92786}{a}}{\color{#129eaf}{c}}}}{2{\color{#c92786}{a}}}

x=2a−b±b2−4ac

Once in standard form, identify a, b and c from the original equation and plug them into the quadratic formula.

2

+

6

+

8

=

0

x^{2}+6x+8=0

x2+6x+8=0

=

1

a={\color{#c92786}{1}}

a=1

=

6

b={\color{#e8710a}{6}}

b=6

=

8

c={\color{#129eaf}{8}}

c=8

=

−

6

±

6

2

−

4

⋅

1

⋅

8

√

2

⋅

1

Answer 2

x² + 6x + 8 = 0

=> x² + 4x + 2x + 8 = 0

=> x(x + 4) + 2(x + 4) = 0

=> (x + 2)(x + 4) = 0

Therefore, x = -2 and x = -4.

Hope it helps !