Question

find the roots of the equation x2-root 3x=6

Answer 1

Step-by-step explanation:

${x}^{2} - \sqrt{3} \times x = 6$

${x}^{2} - 2 \sqrt{3} x + \sqrt{3} x - 6 = 0$

$x(x - 2 \sqrt{3} ) + \sqrt{3} (x - 2 \sqrt{3} ) = 0$

$(x - 2 \sqrt{3} )(x + \sqrt{3} )$

$x = 2 \sqrt{3}$

OR

$x = - \sqrt{3}$

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