Question

Find the roots of the equation x2+x-182=0

Answer 1

Step-by-step explanation:

x²+x-182=0

a=1;b=1;c=-182

D=b²-4ac

D=1²-4(1)(-182)

D=1+728

D=729

√D=27

x=(-b+-√D)/2a

x=(-1+-27)/2(1)

x=(-1+-27)/2

x=(-1+27)/2 or x=(-1-27)/2

x=26/2 or x=-28/2

x=13 or x=-14

Answer 2

Answer:

Given:

A Quadratic Equation x² + x - 182 = 0

To Find:

Roots of this equation

Solution:

x=[ -b ± (b²-4ac)½} / 2a

here a =1

b =1

c= -182

therefore x= [-1 ± (1² - 4 ×1 × -182)½ ]/ 2 (1)

x = [-1 ±(1 +728)½] / 2

x = [-1 ±(729)½] /2

Either x= -1 +(729)½ /2 or x= -1 -(729)½ /2

x= 13 x=-14