Question

Find the roots of the equation x² + x (c-b) + (c-a) (a - b) = 0 help me plzzz..... i'm posting this qstn for 11th time​

Answer 1

$x = \frac{ - (c - b) \frac{ + }{} \sqrt{ {(c - b)}^{2} - 4(c - a)(a - b)} }{ 2 } \\ = \frac{ - c + b \frac{ + }{} \sqrt{ {c}^{2} - 2cb + {b}^{2} - 4(ac - bc - {a}^{2} + ab} )}{2} \\ = \frac{ - c + b \frac{ + }{} \sqrt{ {c}^{2} - 2cb + {b}^{2} - 4ac + 4bc + 4 {a}^{2} - 4ab} }{2} \\ = \frac{ - c + b \frac{ + }{} \sqrt{ {c}^{2} + 2bc + {b}^{2} - 4 {ac}^{} - 4ab + 4 {a}^{2} }}{2} \\ let \: the \: value \: under \: square \: root \: be \: t \\ x = \frac{ - c + b \frac{ + }{} t}{2} \\ x _{1} = \frac{ - c + b + t}{2} \: \: \: \: \: \: x _{2} = \frac{ - c + b - t}{2}$