Math, asked by abhij2970, 1 year ago

find the roots of the equation x2+x-p(p+1)=0

Answers

Answered by ArfaAlam
17
x2+x-p(p+1)=0
x2+(p+1)x-px-p(p+1)=0
x(x+p+1) -p(x+p+1)=0
(x+p+1)(x-p)=0
x=-p-1, p

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