Question

Find the roots of the equation x2+x-p(p+1)=0, where p is a constant. ​

Answer 1

Answer:

root1=-p,root2=p-1

Explanation:

sum of root alpha+beta=-1

a+b=-1

a=-1-b

product of root alpha×beta=-p(p+1)

a×b=-p(p+1)

-(1+b)×b=-p²-p

-b²-b=-p²-p

p-b=b²-p²

p-b=(b-p)(p+b)

1=-(p+b)

b=-p

a=-1-(-p)

a=p-1