Math, asked by harsh7992, 1 year ago

Find the roots of the equation x² + x − p(p + 1) = 0, where p is a constant

Answers

Answered by gaurav2013c
16
x^2 + x - p(p+1) = 0

=> x^2 + (p+1)x - px - p(p+1) = 0

=> x( x + p + 1) - p (x + p + 1) = 0

=> (x - p) (x + p + 1) = 0

Roots are P and - (p + 1)

harsh7992: i don't understand what is a first step
gaurav2013c: steps to split the middle term :- divide the product of coficient of x^2 and constant term, such that their sum is the coficient of x
harsh7992: oo
harsh7992: i understand thank you bro
Answered by ɪᴛᴢᴛʀᴀɢɪᴄɢɪʀʟ
6

x^2 + x - p(p+1) = 0

=> x^2 + (p+1)x - px - p(p+1) = 0

=> x( x + p + 1) - p (x + p + 1) = 0

=> (x - p) (x + p + 1) = 0

Roots are P and - (p + 1)

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