find the roots of the equation xsqr+4x+5=0
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x^2 + 4x + 5 = 0
x^2+(5x-x)+5=0
x (x+5)+1 (x+5)=0
Therefore, x+1=0 and x+5=0
We will get. x=-1. and.x=-5
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x^2+(5x-x)+5=0
x (x+5)+1 (x+5)=0
Therefore, x+1=0 and x+5=0
We will get. x=-1. and.x=-5
Follow me
GAnshu1:
noo the answrr is wrong
it has no real roots
bcs it dnt satisfy b^2-4ac formula
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