Find the roots of the equation xsquare-3x-m(m+3)=0 where m is a constant
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Answered by
2
Answer:
X^2 - 3x - m(m+3) = 0
=> x^2 + mx - (m+3)x- m(m+3) = 0
=> x(x+m) - (m+3)(x+m) = 0
=> (x+m) (x-m-3) = 0
x = - m and m+3
Roots are - m and m+3
Hope it helps you Mark as brainliest please
Answered by
1
Answer:
[x+m][x-(m+3)]
Step-by-step explanation:
x^2-3x-m(m+3)
x^2-(m+3)x+mx-m(m+3)
x[x-(m+3)]+m[x-(m+3)]
[x+m][x-(m+3)]
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