Question

find the roots of the equation xsquare+x-p(p+1) =0​

Answer 1

Step-by-step explanation:

x² + x - p(p + 1) = 0

=> x² + x - p² - p = 0

=> x² - p² + x - p = 0

=> (x + p)(x - p) + (x - p) = 0

=> (x - p)(x + p + 1) = 0

Either, x - p = 0 or, x + p + 1 = 0

=> x = p and x = - p - 1