Question

Find the roots of the following: −2x+3=−8x^2

Answer 1

Answer:

sorry but pure pic nai aya

Answer 2

Step-by-step explanation:

-2x+3=8x^2

or, 8x^2-2x+3=0

According to the Sridharacharya equation we can say

x={(-b)+- route of (b^2-4ac)}/2a

or, x={-(-2)+-route of (4-96)/16 (here b=-2,a=8,c=+3)

or,x=(2+-route of - 92) /16

or, x=(2+-route of 92i) /16 (we know i=route of - i)

or, x=(2+-2route of 23i)/16

or, x=(1+route23i)/8 (for + sign)

or, x=(1-route23i) /8 (for - sign)