Question

find the roots of the following 4x+3y=12​

Answer 1

The given equation is 4x + 3y = 12

For x=0,  

4×0 + 3y = 12

⇒ 3y = 12 - 0

⇒ 3y = 12

⇒ y = 12/3  

⇒ y = 4

So (0,4) is a solution.

For x=1,  

4×1 + 3y = 12

⇒ 3y = 12 - 4

⇒ 3y = 8

⇒ y = 8/3  

So (1,8/3) is a solution.

For x=2,  

4×2 + 3y = 12

⇒ 3y = 12 - 8

⇒ 3y = 4

⇒ y = 4/3  

So (2,4/3) is a solution.

For x=3,  

4×3 + 3y = 12

⇒ 3y = 12 - 12

⇒ 3y = 0

⇒ y = 0/3  

⇒ y = 0

So (3,0) is a solution.

Four solutions are: (0,4); (1,8/3); (2,4/3); (3,0)