Question

find the roots of the following equation . 1/x+y - 1/x-7 = 11/30​

Answer 1

Answer:

1 Or 2 roots of given Quadratic equation.

Explanation:

Given

\frac{1}{x+4}-\frac{1}{x-7}=\frac{11}{30}

\implies \frac{[x-7-(x+4)]}{(x+4)(x-7)}=\frac{11}{30}

\implies\frac{x-7-x-4}{x^{2}-7x+4x-28}=\frac{11}{30}

\implies\frac{-11}{x^{2}-3x-28}=\frac{11}{30}

Do the cross multiplication, we get

=> 30 = 11(x²-3x-28)/(-11)

Answer 2

Step-by-step explanation:

1(x-7)-1(x+y)/(x+y)(x-7) =11/30

x-7-x-y/x(x-7) +y(x-7) =11/30

-7-y/x^2-7x+xy-7y=11/30

30(-7-y)=11(x^2-7x+xy-7y)

-210-30y=11x^2-77x+11xy-77y

-210-11x^2+77x-11xy+77y-30y

-11x^2+77x-11xy+47y