Find the roots of the following equation
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Answer:
The roots of the quadratic equation are
x = ( 3 + √13 ) / 2 and x = ( 3 - √13 ) / 2.
Step-by-step-explanation:
The given quadratic equation is
2x - ( 2 / x ) = 6.
We have to find the roots of the quadratic equation.
Now,
2x - ( 2 / x ) = 6
⇒ ( 2x² - 2 ) / x = 6
⇒ 2x² - 2 = 6x
⇒ 2x² - 2 - 6x = 0
⇒ 2x² - 6x - 2 = 0
⇒ 2 ( x² - 3x - 1 ) = 0
⇒ x² - 3x - 1 = 0
Comparing with ax² + bx + c = 0, we get,
- a = 1
- b = - 3
- c = - 1
Now,
b² - 4ac = ( - 3 )² - 4 * 1 * ( - 1 )
⇒ b² - 4ac = 9 + 4
⇒ b² - 4ac = 13
Now, by quadratic formula,
x = [ - b ± √( b² - 4ac ) ] / 2a
⇒ x = [ - ( - 3 ) ± √13 ] / ( 2 * 1 )
⇒ x = ( 3 ± √13 ) / 2
⇒ x = ( 3 + √13 ) / 2 OR x = ( 3 - √13 ) / 2
∴ The roots of the quadratic equation are
x = ( 3 + √13 ) / 2 and x = ( 3 - √13 ) / 2.
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