Find the roots of the following equation if they exist by applying the quadratic formula. 2x^2+ax-a^2=0
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Answer:
D=(a)^2-4(2)(-a^2)=a^2+8a^2=9a^2
√D=√(9a^2)=3a
x=[(-a)-3a]/4
=(-4a/4)=(-a)
or
x=[(-a)+3a]/4=a/2
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