Find the roots of the following equations 1/x - 1/x-2=3 ; for which x≠0, 2
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1/x - 1/x-2=3
x-2 -x/x²-2x =3
-2=3(x²-2x)
-2=3x²-6x
3x²-6x+2=0 (by quadratic formula)
a=3 b=-6 c=2
D=b²-4ac=(-6)²-4(3)(2)=36-24=12
x=-b+√D/2a or -b-√D/2a
=-(-6)+√12/2(3) or -(-6)-√12/2(3)
=6+2√3/6 or 6-2√3/6
=1+ 1√3/3 or 1- 1√3/3
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