Math, asked by singhayush2125, 11 months ago

Find the roots of the following polynomial equation: 1. 5x-3=0. 2. 9x^2-4=0. 3.5x^2-9=0. 4.(x+1)(3x+2)=0. 5.(x+2)(x-3)(2x-7)=0. ​

Answers

Answered by conjureroman
2

Step-by-step explanation:

1. 5x-3=0

=>x=3/5

2. 9x²-4=0

=> (3x+4)(3x-4)=0

=> x=3/4 & x= -3/4

3. 5x²-9=0

=> (√5x+9)(√5x-9)=0

=> x=9/√5 &. x= -9/√5

4. (x+1)(3x+2)=0

=> x= -1 & x= -3/2

5. (x+2)(x-3)(2x-7)=0

=> x= -2 , x=3 & x=7/2

In all the above question you have to just make an quadratic and linear equation and solve by putting it equal to zero.

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