Question

find the roots of the following polynomial equations :- (x-1)(3x+2​

Answer 1

Answer:

+1 and -3/2

Step-by-step explanation:

you got into 2 factors

that's it

please mark as brainliest

Answer 2

Answer:

$(x - 1)(3x + 2) \\ = 3 {x}^{2} + 2x - 3x - 2 \\ = 3 {x}^{2} - x - 2 \\ \\ 3 {x}^{2} - x - 2 = 0 \\ 3 {x}^{2} - 3x + 2x - 2 = 0 \\ 3x(x - 1) + 2(x - 1) = 0 \\ (x - 1)(3x + 2) = 0 \\ x - 1 = 0 \: \: or \: \: 3x + 2 = 0 \\ x = 1 \: \: or \: \: 3x = - 2 \\ \large{ \boxed{x = { \underline{ \underline{1}}} \: \: or \: \: x = { \underline{ \underline{ \frac{ - 2}{3} }}}}}$