Question

find the roots of the following quact equation

x^2-3x-10=0​

Answer 1

Answer:

x=-5,2

Step-by-step explanation:

The given equation is $x^{2} -3x-10=0$.

So by factorization we get the following:

$x^{2}-3x-10 = x^{2}+2x-5x-10 = x(x+2)-5(x+2) = (x-5)(x+2)$

⇒(x-5)(x-2)=0  [∵Given]

⇒x=5,-2

Hope this helps you.