Question

Find the roots of the following
quadrathic equation using
$2 {x}^{2} - 2 \sqrt{2x} + 1 = 0$
formula​

Answer 1

Step-by-step explanation:

answer is above pucture

Answer 2

Solution:-

Given Equation :- 2x²-2√2x +1 =0

⟹ 2x² -√2x- √2x +1=0 [Splitting term]

⟹ √2x(√2x-1 ) - 1(√2x-1) =0

⟹ (√2x-1)(√2x-1) =0

⟹ (√2x-1)² = 0

∴ x = 1/√2 it has real and equal roots