Question

find the roots of the following quadratic equation​

Answer 1

Answer:

Step-by-step explanation:

$2x^{2} +5x-3=0\\2x^{2} +2x+3x-3=0\\2x(x+1)-3(x+1)=0\\(2x-3)(x+1)=0\\x=\frac{3}{2} \\ or\\x=-1 rejected\\x=\frac{3}{2}$

Answer 2

Step-by-step explanation:

2x sq - (-2-3)x -3=0

2x sq +2x + 3x - 3 =0

2x (x + 1) + 3 (x + 1)=0

(2x +3) = 0 ; (x+1 ) = 0

or, x = - 3/2 ; or, x = -1

Answer: The roots of this equation are - 3/2 and -1