Question

find the roots of the following quadratic equation 4x^2+4√3x+3=0​

Answer 1

Answer:

x = -(root3)/2

Step-by-step explanation:

=> 4x^2+4√3x+3=0​

=> 4x^2+2√3x + 2√3x +3 = 0​

=> 2x(2x+√3) + √3(2x+√3) = 0

=> (2x+√3)^2 = 0

=> x = -(root3)/2

Hope this helps.....

Answer 2

Step-by-step explanation:

/ = root

4x^2 + 2/3x + 2/3x + 3 = 0

2x(2x + /3) + /3(2x + /3) = 0

(2x + /3)(2x + /3) = 0

x = -/3÷2, -/3÷2