Question

find the roots of the following quadratic equation by factorisation : x-3/x=2​

Answer 1

x-3/x=2

x²-3=2x

x²-2x-3=0

x²-3x+x-3=0

x(x-3)+1(x-3)=0

(x-3)(x+1)=0

x=3,-1

Answer 2

Answer:

Given that x-3/x = 2

by solving it you will get,

x2-2x-3 =0

Here a=1, b=-2 , c=-3

D=b2-4ac

=> (-2)2- 4×1×(-3)

=> 16

alpha= -b+√D/2a

= -(-2)+√16/2×1

= 6/2=3

beta = -b-√D/2a

= -(-2)-√16/2×1

=-2/2= -1

Therefore the two roots are 3 & -1 .