Question

Find the roots of the following quadratic equation by factorisation:(Question in attachment )No spam××××​

Answer 1

Answer:

x = -a, x = -b

Step-by-step explanation:

(1/a + b + x) = (1/a) + (1/b) + (1/x)

=> (1/a + b + x) - (1/x) = (1/a) + (1/b)

=> [x - (a + b + x)]/x(a + b + x) = (a + b)/ab

=> [x - a - b - x]/x(a + b + x) = (a + b)/ab

=> [-a - b]/x(a + b + x) = (a + b)/ab

=> [-(a + b)]/x(a + b + x) = (a + b)/ab

=> -ab(a + b) = (a + b) * x(a + b + x)

=> -ab(a + b) - (a + b) * x(a + b + x) = 0

=> (a + b)[x(a + b + x) + ab] = 0

=> x(a + b + x) + ab = 0

=> a^2 + xb + x^2 + ab = 0

=> x(x + a) + b(x + a) = 0

=> (x + a)(x + b) = 0

=> x = -a,x = -b

#Hope my answer helped you!