Question

Find the roots of the following quadratic equation by applying quadratic formula.

(i) 2x² - 7x + 3 = 0​

Answer 1

$\huge\underline\mathbb{SOLUTION:-}$

$\mathsf \red {(i)\:2x^2 - 7x + 3 = 0}$

• Comparing quadratic equation 2x² - 7x + 3 = 0 with general form ax² + bc + c = 0, We get a = 2, b = -7 and c = 3

$\underline \mathsf {Putting\:these\:values\:in\:quadratic\:formula:- }$

$\mathsf {x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} }$

$\mathsf {x = \frac{7 \pm \sqrt{(-7)^2 - 4(2)(3)}}{2\times2} }$

$\implies \mathsf {x = \frac{7 \pm \sqrt{49 - 24}}{4} }$

$\implies \mathsf {x = \frac{7 \pm 5}{4} }$

$\implies \mathsf {x = \frac{7 + 5}{4}, \frac{7 - 5}{4} }$

$\implies \mathsf \blue {x = 3,1/2}$

Answer 2

Answer:

2x²-7x+3 =0

2x²-6x-x+3 = 0

2x(x-3)-1(x-3) = 0

(x-3)(2x-1) = 0

x-3 =0 ,. 2x-1 = 0

x = 3. ,. 2x = 1

x = 1/2

hope it will help you .

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