Question

Find the roots of the following quadratic equation by factorisation: 1) 2x²-x+1/8=0.

Answer 1

Step-by-step explanation:

${2x}^{2} - x + \frac{1}{8} = 0$

${16x}^{2} - 8x + 1 = 0$

${16x}^{2} - 4x - 4x + 1 = 0$

$4x(4x - 1) - 1(4x - 1)$

$(4x - 1)(4x - 1)$

$x = \frac{1}{4}and \: x = \frac{1}{4}$

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