Question

find the roots of the following quadratic equation by factorisation: b) 6x²-x-2=0​

Answer 1

Answer:

$(2x + 1)(3x - 2)$

Step-by-step explanation:

Here,

$6 {x}^{2} - x - 2$

or,

$6 {x}^{2} + 3x - 4x - 2$

factor outing

$3x(2x + 1) - 2(2x + 1)$

now ,

$(2x + 1)(3x - 2)$

I am done.

Answer 2

6x^2 -x -2=0

Or, 6x^2 +3x -4x -2=0

Or, 3x(2x+1) - 2(2x+1)= 0

Or, (2x+1)(3x-2)=0

Thus, 2x+1=0

Or, 2x= -1

Or, x= -1/2

OR

3x-2=0

3x=2

x= 2/3

Answer: Roots of x are -1/2, 2/3.