Question

find the roots of the following quadratic equation by factorisation : x^2-3x-10=0​

Answer 1

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Answer 2

Answer:

heya mate ☺

$x ^{2} - 3x - 10 = 0 \\ = > x ^{2} - (5 - 2)x - 10 = 0 \\ = > x^{2} - 5x + 2x - 10 = 0 \\ = > x(x - 5) + 2(x - 5) = 0 \\ = > (x - 5)(x + 2) = 0 \\ \\ either \: (x - 5) = 0 \\ = > x = 5 \\ \\ or \: x + 2 = 0 \\ = > x = - 2$

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