Question

find the roots of the following quadratic equation by factorisation:
100x^2-20x+1=0

Answer 1

Heya !!



100X² - 20X + 1 = 0



100X² - 10X - 10X + 1 = 0


10X ( 10X- 1 ) - 1 ( 10X - 1 ) = 0


( 10X - 1 ) ( 10X - 1 ) = 0



( 10X - 1 ) = 0


X = 1/10


Hence,


the given quadratic equation have two real and equal roots which are 1/10 and 1/10.

Answer 2

Answer:

Step-by-step explanation:

By spliting the middle termmethod:

100x^2-20x+1 = 0

ac = 100

b = -20

Therefore the terms are -10 and -10

=> 100x^2-10x-10x+1 = 0

=> 10x (10x-1)-1 (10x-1) = 0

=> (10x-1) (10x-1)

=> 10x-1 = 0 OR 10x-1 = 0

=> x = 1/10 OR x = 1/10

Therefore the roots are 1/10 and 1/10.

Hence solved.