Question

find the roots of the following quadratic equation by the factorization method: 3√2x2-5x-√2=0​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Answer:

x = $\frac{\sqrt{2} }{3} \ and\ \frac{1}{\sqrt{2} }$

Step-by-step explanation:

$3\sqrt{2}x^{2} - 5x - \sqrt{2}$ = 0

Find product of coefficient of x2 and constant

$3\sqrt{2} * \sqrt{2}\\=3*2\\=6$

find two factors of 6 that add or subtract to -5.

-3 * -2 = 6, -3 + (-2) = -5

thus factors will be -3 and -2

expand -5x as -3x and -2x:

$3\sqrt{2}x^{2} - 3x - 2x - \sqrt{2}$ = 0

Take 3x from first two terms and √2 from last two terms:

$3x(\sqrt{2}x - 1 ) - \sqrt{2}(\sqrt{2}x - 1) \\\\(3x - \sqrt{2}) (\sqrt{2}x - 1)$

Equate each term to 0,

We will get x = $\frac{\sqrt{2} }{3} \ and\ \frac{1}{\sqrt{2} }$