Question

Find the roots of the following quadratic equation, if it exist
5X²_7X-6=0​

Answer 1

5x² - 7x - 6 = 0

Here,

• It is of the form ax² + bx + c = 0, so

a = 5, b = (- 7), c = (- 6)

Now,

• If discriminant of the equation is equal to 0, then it has two real equal roots.

• If discriminant of the equation is more than 0, then it has two real & distinct roots.

• If discriminant of the equation is less than 0, then it has non-real roots.

So,

Discriminant = b² - 4ac

= (-7)² - 4(5)(-6)

= 49 + 120 = 169

°.° Discriminant > 0 i.e. D = 169

Then,

Roots of the equation are :

$\boxed{ \tt \frac{ - b \pm \sqrt{ {b}^{2} - 4ac } }{2a} } \: \: or, \:\boxed{ \tt \frac{ - b \pm \sqrt{D } }{2a} }$

Thus,

$\rm { {1}^{st} } \: \text{Root of the equation } = \frac{ - ( - 7) + \sqrt{169} }{2(5)} \\ \\ \bf = > \frac{7 + 13}{10} \: \: \: \: = \frac{20}{10} \: \: \: = \red 2$

$\rm { {2}^{nd} } \: \text{Root of the equation } = \frac{ - ( - 7) - \sqrt{169} }{2(5)} \\ \\ = > \frac{7 - 13}{10} \: \: \: = \frac{ - 6}{10} \: \: \: = \red{ \frac{ - 3}{5} }$

Answer 2

Answer:

green spelling is this your's bio's one is wrong