Question

find the roots of the following quadratic equation (x+3)(x-1)= 3(x - 1/3 )

PLZZZ help

Answer 1

$\textbf {Answer}$ :

The roots of the given Quadratic Equation are 2 and - 1.

$\textbf {Step by step explanation}$ :

First of all, we will need to change the given equation in the form of a Quadratic Equation by opening the brackets.

$(x + 3)(x - 1) = 3(x - \frac{1}{3}) \\ \\ {x}^{2} - x + 3x - 3 = 3x - 1 \\ \\ {x}^{2} - x - 2 = 0 \\ \\Splitting \: the \: middle \: term, \\ \\ {x}^{2} - 2x + x - 2 = 0 \\ \\ x(x - 2) + 1(x - 2) = 0 \\ \\ (x - 2)(x + 1) = 0 \\ \\ \therefore \: x = 2 \: or \: - 1$

So, we get the roots of the given Quadratic Equation as 2 and - 1.

♥️${Be} ^{Brainly}$♥️

Answer 2

Hope this helps you my friend.. ☺