find the roots of the following quadratic equation x2 + x - 156 = 0
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Answered by
78
x^2 + x - 156 =0
x^2 + 13x - 12x - 156 = 0
x(x + 13) - 12(x + 13) = 0
(x+13) (x-12) =0
x= - 13 and 12
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x^2 + 13x - 12x - 156 = 0
x(x + 13) - 12(x + 13) = 0
(x+13) (x-12) =0
x= - 13 and 12
hope it helped u
if yes then mark it as BRAINLIEST
sweety263:
thankxx
Answered by
19
x^2+13x-12x-156 =0
x (x+13)-12 (x+13)=0
(x-12)(x+13)=0
x=12 ,-13
x (x+13)-12 (x+13)=0
(x-12)(x+13)=0
x=12 ,-13
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