Question

find the roots of the following quadratic equations by factorisation x(x+4)=12​

Answer 1

Step-by-step explanation:

X(X+4)=12

x²+4x=12

x²+4x-12=0

x²+6x-2x-12=0

X(X+6)-2(X+6)=0

(X+6)(x-2)

X= 2 and -6

Answer 2

Step-by-step explanation:

x(x + 4)=12

x^2+4x = 12

x^2 + 4x - 12 = 0

factors of 12 is -6 and -2

x^2 - 6x - 2x - 12 = 0

x(x - 6) - 2(x -6)

(x-6) (x-2) = 0

x - 6 =0. or. x - 2 = 0

x = 6. or. x = 2