Question

Find the roots of the following quadratic equations by factorisation.​

Answer 1

Answer:

x = 5 or x = -2

Step-by-step explanation:

this are the roots of quadratic equation

Answer 2

${\large{\textsf{\underline{\underline{\red{Given :}}}}}}$

$x^2-3x-10=0$

${\large{\textsf{\underline{\underline{\red{Solution :}}}}}}$

$\implies x^2-3x-10$

$\implies x^2+2x-5x-10$

$\implies x(x+2)-5(x+2)$

$\implies (x-5)(x+2)$

Now equating the factors to zero we get,

$(x-5)(x+2)=0$

$x+2=0\:\: \text{gives} \:\:x=-2 \:\text{or} \:\:x+5=0\:\text{gives}\:\:x=5$

Therefore the roots are, $-2,5$

(NOTE : Some equations which are not quadratic can be solved by reducing them to quadratic equations by suitable substitutions.)