Find the roots of the following quadratic equations by factorisation:
i 2-3x - 100 i 2x2+x-6=0
1
iv. 2x²
-X+0
8
i Vr+7x+52 0
. 1007 - 20x + 1 = 0
vii. 3x - 5x+2=0 vii.
vii
. -2=2(x 0)
vi x(x + 4) 12
3
ix. 367 - 42 - 5(x - 4) - 12
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find the roots factors affection of the following in the max particles of the body
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Answer:
i) 2x² + x – 6 = 0
= 2x² + 4x – 3x – 6 = 0
= 2x ( x + 2 ) – 3 ( x + 2 ) = 0
= ( x + 2 ) ( 2x – 3 ) = 0
= x + 2 = 0 (or) 2x – 3 = 0
= x = –2 (or) 2x = 3
= x = –2 (or) x = 3/2
= x = –2 (or) 3/2
since the roots of this quadratic equation is –2 (or) 3/2
vii) 3x²–5x + 2 = 0
= 3x²– 2x – 3x + 2 = 0
= x( 3x – 2 ) – 1 (3x – 2) = 0
= ( 3x – 2) ( x – 1 ) = 0
= 3x – 2= 0 (or) x – 1 = 0
= 3x = 2 (or) x = 1
= x = 2/3 (or) x = 1
= x = 2/3 (or) 1
roots of quadratic equation is 2/3 (or) 1
. Hope this helps you
#Ravalika Rajula
: )
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