Find the roots of the following quadratic equations by factorisation 1) x²-3x-10=0
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x^ 2 - 3x -10 = 0
we need to find 2 nos such that their sum is 3 and product is 10
x^2+2x -5x -10 = 0
x(x+2) -5(x+2) = 0
(x+2) (x-5) = 0
x +2 = 0
x = -2
x-5 = 0
x= 5
the two roots are -2 and 5
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Answer:
x²-3x-10=0
x²-5x+2x-10=0
x(x-5)+2(x-5)=0
(x+2) (x-5) = 0
x+2=0. x-5=0
x=-2. x=5
So, x=-2 and x=5 are the roots of this quadratic equation....
Thanks
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