Question

Find the roots of the following quadratic equations by factorisation:

(i) x2 -3x – 10 = 0

(ii) 2x2 + x – 6 = 0

(iii) √2x2 + 7x + 5√2 = 0


(_-_)​

Answer 1

Answer:

it's answer is silar to this

Step-by-step explanation:

x

2

−7x+

5

=0

x

1,2

=

2a

−b±

b

2

−4ac

x=

2⋅1

−(−7)±

(−7)

2

−4⋅1

5

=

2

7±

49−4

5

Answer 2

Answer:

(iii) √2 x2 + 7x + 5√2=0

Considering the L.H.S. first,

⇒ √2 x2 + 5x + 2x + 5√2

⇒ x (√2x + 5) + √2(√2x + 5)= (√2x + 5)(x + √2)

The roots of this equation, √2 x2 + 7x + 5√2=0 are the values of x for which (√2x + 5)(x + √2) = 0

Therefore, √2x + 5 = 0 or x + √2 = 0

⇒ x = -5/√2 or x = -√2