Question

Find the roots of the following quadratic equations by factorisation : 15x2 – 41 x + 28 = 0​

Answer 1

Answer:

The roots of the quadratic equation are 7/5 and 4/3

Step-by-step explanation:

We have been given a quadratic equation, an equation of degree 2 is called a quadratic equation, we can find the roots of the equation by equating the quadratic equation to zero, we can find the roots by factorisation method or formula method, here we have to find the roots by factorisation method

$15x^{2} -41x+28=0\\15x^{2} -21x-20x+28=0\\3x(5x-7)-4(5x-7)=0\\(5x-7)(3x-4)=0$

5x-7=0  or    3x-4=0

$x=\frac{7}{5}$     or    $x=\frac{4}{3}$

The roots of the quadratic equation are $\frac{7}{5}$ and $\frac{4}{3}$