Find the roots of the following quadratic equations by factorisation :
15x^2-10√6x+10=0
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Answer:
Step-by-step explanation:
15x^2 - 10√6x + 10 = 0
5 ( 3x^2 - 2√6x + 2) = 0
3x^2 - 2√6x + 2 = 0 / 5
3x^2 - 2√6x + 2 = 0
3x^2 - 2√6x + 2 = 0
Comparing it with ax^2 + bx + c = 0
a = 3 b = - 2√6 c = 2
D = b^2 - 4ac
= ( -2√6 )^2 - ( 4 x 3 x 2 )
= 2 4 - 2 4
= 0
x = ( -b ± √D ) / 2a
= [ ( -2√6 ) ± √0 ] / 2(3)
= 2√6 / 6
= √6 / 3
= ( √2 x √3 ) / ( √3 x √3 )
= √2 / √3
Therefore roots are √2/√3 and √2/√3.
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