Math, asked by anyasingh6753, 11 months ago

Find the roots of the following quadratic equations by factorisation :
15x^2-10√6x+10=0

Answers

Answered by parashuramnalla
3

Answer:

Step-by-step explanation:

15x^2 - 10√6x + 10 = 0

5 ( 3x^2 - 2√6x + 2) = 0

3x^2 - 2√6x + 2 = 0  / 5

3x^2 - 2√6x + 2 = 0

3x^2 - 2√6x + 2 = 0

Comparing it with ax^2 + bx + c = 0

a = 3   b = - 2√6  c = 2

D = b^2 - 4ac

 = ( -2√6 )^2 - ( 4 x 3 x 2  )

 = 2 4 - 2 4

 = 0

x = ( -b ± √D ) / 2a

 = [ ( -2√6 ) ± √0 ] / 2(3)

 = 2√6 / 6

= √6 / 3

= ( √2 x √3 )   / ( √3 x √3 )

 = √2 / √3

Therefore roots are √2/√3 and √2/√3.

Similar questions