Question

Find The Roots of the following Quadratic Equations by the  factorization method 2Y^2 +5/3 Y-2=0​

Answer 1

Answer:

$2 {y}^{2} + \frac{5}{3} y - 2 = 0$

Multiplying both side with 3.

$6 {y}^{2} + 5y - 6 = 0 \\ \\ 6 {y}^{2} + 9y - 4y - 6 = 0 \\ \\ 3y(2y + 3) - 2(2y + 3) = 0 \\ \\ (2y + 3) \: \: (3y - 2) = 0$

If 2y + 3 = 0

$2y = - 3 \\ \\ y = \frac{ - 3}{2}$

If 3y - 2 = 0

$3y = 2 \\ \\ y = \frac{2}{3}$

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