Question

Find the roots of the following quadratic equations by the factorisation method:

2X2
+
5/3x – 2 = 0​

Answer 1

Answer:

x = -3/2; x = 2/3

Step-by-step explanation:

$2x^2+\frac{5}{3}x-2 = 0$

$6x^2+5x-6=0$ (multiply both sides by 3)

now we know,

$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

so, $x = \frac{-5-\sqrt{5^2-4\cdot \:6\left(-6\right)}}{2\cdot \:6} = \frac{-5-\sqrt{169}}{2\cdot \:6} = \frac{-5-13}{12} = -\frac{18}{12} = -\frac{3}{2}$

or,

$x = \frac{-5+\sqrt{5^2+4\cdot \:6\cdot \:6}}{2\cdot \:6} = \frac{-5+\sqrt{169}}{2\cdot \:6} = \frac{-5+13}{12} = 8/12 = \frac{2}{3}$

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