Question

Find the roots of the following quadratic equations (if they exist) by the method of completing
the square.x^2-4√2x+6=0​

Answer 1

Answer:

your answer is in the picture!!!!!!!!

Answer 2

Answer:

Step-by-step explanation:

x^2-4√2x+6=0

x^2-2×x×2√2+(2√2)^2-(2√2)^2+6=0

(x-2√2)^2-(2√2)^2+6=0

(x-2√2)^2-4×2+6=0

(x-2√2)^2-8+6=0

(x-2√2)^2-2=0

(x-2√2)^2=2

x-2√2=√2

x=√2+2√2

x=3√2