Find the roots of the following quadratic equations (if they exist) by the method of completing the
square : x²+5x+7=0
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Answer:
no real roots
Step-by-step explanation:
x2 + 5x + 7 = 0
transfer 7 on other side
x2 + 5x = -7
divide x2 coefficient on both sides
x2 + 5x = -7
now add (5/2) square on both sides
x2 + 5x + (5/2) square = -7 + (5/2) square
this can be written as (a + b)square form
then, (x+5/2) square = -7 + 25/4
(x + 5/2) square =( -28 + 25)/4
(x + 5/2) square = (-4/4)
(x + 5/2) square = -1 < 0
but (x + 5/2) square cannot be negative for real value of x. so, there is no real value satisfing the given equation. therefore the given equation has no real roots.
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