Math, asked by minazbegum410, 19 days ago

find the roots of the following quadratic equations if they exist. X square + 5 is equals to minus 6​

Answers

Answered by azalfaizhar401
0

Step-by-step explanation:

Roots of given equationx^2+5=-6xx

2

+5=−6x are -1 and -5.

Step-by-step explanation:

Given:

x^2+5=-6xx

2

+5=−6x

We need to find the roots of the quadratic equation by the method of completing square.

Solution:

On Solving the equation we get;

x^2+6x=-5x

2

+6x=−5

Now we can see the co efficient of 'x' is 6.

Now Complete square formula is;

(a+b)^2= a^2+2ab+b^3(a+b)

2

=a

2

+2ab+b

3

In our equation a = xa=x

2ab = 6x2ab=6x

but 6x6x can be written as 2\times 3x2×3x

So we can say that third term c=3c=3

Hence From above we can say that to make complete square we need to add both side by 9.

Adding both side by nine we get;

\begin{gathered}x^2+6x+9=-5+9\\\\x^2+3x+3x+9=4\\\\x(x+3)+3(x+3)=4\\\\(x+3)(x+3)=4\\\\(x+3)^2=4\end{gathered}

x

2

+6x+9=−5+9

x

2

+3x+3x+9=4

x(x+3)+3(x+3)=4

(x+3)(x+3)=4

(x+3)

2

=4

Taking square root on both side we get;

\begin{gathered}\sqrt{(x+3)^2} = \sqrt{4} \\\\x+3= \sqrt{4}\end{gathered}

(x+3)

2

=

4

x+3=

4

Now root have 2 values 1 positive and 1 negative.

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