Question

Find the roots of the following quadratic equations .x2-[root 3 +1]x+root 3=0

Answer 1

x² - (√3 + 1)x + √3 = 0
x² - √3x -x + √3 = 0
x( x - √3) -(x - √3) = 0
(x - √3)(x - 1) = 0
so, (x -1) = 0 and (x - √3) =0
we get, x = 1 and √3

hence, roots of given equation are 1 and √3

Answer 2

x² - [ √3 + 1] x + √3=0

x² - √3x - 1x + √3 = 0

x ( x - √3) -1 ( x - √ 3)=0

( x -1 ) ( x - √ 3) =0

x-1 = 0 OR x - √3=0

x=1 OR x= √3