Question

find the roots of the following quadratic equtiin if they exist by the method of comoleting the square 2x2-7x+3​

Answer 1

COMPLETE SQUARE METHOD:

given here :

==>2x^2-7x+3=0

==>2x^2-7X= -3.

now ,divided by 2 in both sides

we get:

==>x^2-2* 7/4x=-3/2

multiple by (7/4)^2 in both sides.

==>x^2-2*(7/4)x+(7/4)^2=-3/2+(7/4)^2

==>(x-7/4)^2= 25/16

==>(x-7/4)=±5/4

==>x=±5/4+7/4.

now we can take +ve. and. -ve. sign.

then ,if +ve sign

==>x=3.

if -ve sign

==>x=1/2.

THUS:

ROOT OF QUADRATIC EQUATION WILL BE..

==>X=3,1/2.

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